Answer:
[tex]\frac{8}{25} = {e}^{3v - 2u}[/tex]
Step-by-step explanation:
If
[tex]u = \ln(5) \: then \: 5 = {e}^{u} [/tex]
If
[tex]v= \ln(2) \: then \: 2= {e}^{v} [/tex]
We want to write 8/25 in terms of u and v.
We use properties of exponents to get:
[tex] \frac{8}{25} = \frac{ {2}^{3} }{ {5}^{2} } [/tex]
We substitute for 5 and 2 to obtain:
[tex]\frac{8}{25} = \frac{( { {e}^{v}) }^{3} }{ ({ {e}^{u}) }^{2} } [/tex]
This simplifies to:
[tex]\frac{8}{25} = \frac{{ {e}^{3v}}}{ { {e}^{2u} } } [/tex]
This gives us
[tex]\frac{8}{25} = {e}^{3v - 2u}[/tex]