Respuesta :

Answer:

[tex]\frac{8}{25} = {e}^{3v - 2u}[/tex]

Step-by-step explanation:

If

[tex]u = \ln(5) \: then \: 5 = {e}^{u} [/tex]

If

[tex]v= \ln(2) \: then \: 2= {e}^{v} [/tex]

We want to write 8/25 in terms of u and v.

We use properties of exponents to get:

[tex] \frac{8}{25} = \frac{ {2}^{3} }{ {5}^{2} } [/tex]

We substitute for 5 and 2 to obtain:

[tex]\frac{8}{25} = \frac{( { {e}^{v}) }^{3} }{ ({ {e}^{u}) }^{2} } [/tex]

This simplifies to:

[tex]\frac{8}{25} = \frac{{ {e}^{3v}}}{ { {e}^{2u} } } [/tex]

This gives us

[tex]\frac{8}{25} = {e}^{3v - 2u}[/tex]

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