Question

The table of data obtained from WWW.BASEBALL-ALMANAC.COM shows hit information for four well known baseball players. Suppose that one hit from the table is randomly selected. NAME Single Double Triple Home Run TOTAL HITS Babe Ruth 1,517 506 136 714 2,873 Jackie Robinson 1,054 273 54 137 1,518 Ty Cobb 3,603 174 295 114 4,186 Hank Aaron 2,294 624 98 755 3,771 TOTALS 8,468 1,577 583 1,720 12,351 Find P(hit was a Home Run|The hit was made by Ty Cobb ).

Answer 1

Using the probability concept, it is found that:

• P(hit was a Home Run|The hit was made by Ty Cobb) = 0.0663.

• A probability is the number of desired outcomes divided by the number of total outcomes.

• P(hit was a Home Run|The hit was made by Ty Cobb) is the probability that the hit was made by Ty Cobb, given that it was a home run.

From the table, we have that:

• 714 + 137 + 114 + 755 = 1720 home runs were hit.

• Of those, 114 were hit by Ty Cobb.

Then:

$p = \frac{114}{1720} = 0.0663$

P(hit was a Home Run|The hit was made by Ty Cobb) = 0.0663.

To learn more about the probability concept, you can take a look at https://brainly.com/question/15536019