Question

What is the equation of the circle with center (−13, −16) that passes through the point (−10, −16)? A) (x − 13)2 + (y − 16)2 = 9 B) (x + 13)2 + (y + 16)2 = 3 C) (x + 13)2 − (y + 16)2 = 9 D) (x + 13)2 + (y + 16)2 = 9

Answer 1

Answer:

(x +13)² + (y +16)² = 9

Step-by-step explanation:

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equation of the circle

(x +13)² + (y +16)² = r²

now, (-10, -16) passes through the circle.

so, (-10+13)² + (-16 +16) =r²

r = 3

So, equation is

(x +13)² + (y +16)² = 9