Question

Use the following equation to answer questions 2 and 3. (Use the mole ratio for these problems only!)

3NOLaTeX: _22+ HLaTeX: _22O --> 2HNOLaTeX: _33 + NO

2. How many moles of NOLaTeX: _22are required to produce 3.56 mol of HNOLaTeX: _33?

3. How many moles of water react with 2.5 mol of NOLaTeX: _22?

Answer 1

Answer:

5.34 moles of $NO_2$ are required to produce 3.56 mol of $HNO_3$.

0.83 moles of water react with 2.5 moles of $NO_2$.

Explanation:

i) $3NO_2+H_2O\rightarrow 2HNO_3+NO$

Moles of $HNO_3$ we want to produce = 3.56 moles

According to reaction, 2 moles of $HNO_3$ are obtained from 3 moles of $NO_2$

Then 3.56 moles of $HNO_3$ will be obtained from :

$\frac{3}{2}\times 3.56 mol=5.34 mol$ of $HNO_3$

5.34 moles of $NO_2$ are required to produce 3.56 mol of $HNO_3$.

ii)

Moles of $NO_2$ = 2.5 moles

According to reaction,3 moles of $NO_2$ reacts with 1 mole of $H_2O$,then 2.5 moles of $NO_2$ will react with :

$\frac{1}{3}\times 2.5 mol=0.83 mol$ of $H_2O$

0.83 moles of water react with 2.5 moles of $NO_2$.