Question

One hot day at a fair you buy yourself a snowcone. The height of the cone shaped container is 5 in and its radius is 2 in. The shaved ice is perfectly rounded on top forming a hemisphere

Answer 1

Answer:

12π $in^{3}$

Step-by-step explanation:

The question is incomplete.

question: One hot day at a fair you buy yourself a snowcone. The height of the cone shaped container is 5 in and its radius is 2 in. The shaved ice is perfectly rounded on top forming a hemisphere. what is the volume of of the ice in your frozen treat?

check attachment for the figure.

To find out the volume of ice in frozen treat:    $V_{cone} +V_{hemisphere}$

• volume of cone :

$V_{cone}$=  1/3 * π $r^{2}$ h

$V_{cone}$= 1/3 * π* $2^{2}$ *5

$V_{cone}$ = 20π/3 $in^{3}$

• volume of hemisphere:

$V_{hemisphere}$ = 2/3* π* $r^{3}$

$V_{hemisphere}$= 2/3* π* $2^{3}$

$V_{hemisphere}$= 16π/3 $in^{3}$

By adding up the volumes,

Total volume = $V_{cone} +V_{hemisphere}$

                    =20π/3 + 6π/3 = 36π/3  => 12π $in^{3}$

therefore, the volume of of the ice in frozen treat is 12π $in^{3}$

Answer 2

The total volume of the Ice cream is; 12π in³

How to find the volume?

We are told the shape was an ice cream which means that it is made up of a base cone and a hemispherical top.

We are given;

Height of cone; h = 5 in

Radius; r = 2 in

Thus;

Volume of cone is;

V_c = ¹/₃πr²h

V_c = ¹/₃ × π × 2² × 5

V_c = ²⁰/₃π in³

Volume of Hemispherical top is;

V_h = ²/₃πr³

V_h = ²/₃ × π × 2³

V_h = ¹⁶/₃π in³

Thus, total volume is;

V = ²⁰/₃π + ¹⁶/₃π

V = 12π in³

Read more about Volume of Composite shapes at; https://brainly.com/question/13175744