Question

a population of fruit flies where wing shape is determined by one pair
of alleles: C is normal, c is curly-wings. A population of 1000 flies includes
100 curly-winged flies. In this population, what's 2pq?

Answer 1

The value of 2pg in the given population is 0.432

Explanation:

Given:

C is normal

c is curly wings

So the homozygous dominant condition would be CC

Heterozygous condition would be Cc

Recessive condition would be cc

According to Hardy Weinberg principle,

p² + 2pq + q² = 1

and

p + q = 1

Here,

q² = cc = 100

q² = 100 / 1000

q = √0.1

q = 0.316

So,

p + q = 1

p + 0.316 = 1

p = 0.684

Thus, 2pq would be:

$= 2 X (0.684) X (0.316)\\\\= 0.432$

Therefore, the value of 2pg in the given population is 0.432