Question

The bottle of Wang resin you have been provided with indicates the quantity of surface linker to be 0.75 mmol/g. The bottle contains 675mg resin, and you use the remainder in your synthesis. How many mmol linkers are present on this mass of resin

Answer 1

Answer:

$n_{linerks}=0.506mmol$

Explanation:

In this case, a mole-mass relationship is enough to compute the amount in mmol of the linkers that are present on such mass of resin as shown below:

$n_{linerks}=675mg*\frac{1g}{1000mg}*\frac{0.75mmol}{1g} \\n_{linerks}=0.506mmol$

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