Question

Can you answer this? The teacher messed up so the equation you have to transform to log is the one written in pencil. Please ignore what is written under it

Answer 1

Answer:

Statement 2

Step-by-step explanation:

T = 2pi × sqrt(l/g)

Apply log both sides

log(T) = log(2pi × sqrt(l/g))

log(T) = log(2) + log(pi) + ½log(l/g)

log(T) = log(2) + log(pi) + ½[log(l) - log(32)]

log(T) = log(2) + log(pi) + ½log(l) - ½log(32)

Answer 2

Answer: 2

Step-by-step explanation:

so you have that $T = 2pi*\sqrt{\frac{l}{g} }$

log both sides

logT = log2 + logπ + $\frac{log\frac{l}{g} }{2}$

logT = log2 + logπ + $\frac{logl - logg }{2}$

plug in 32 for g and separate the fraction into two

= log2 + logπ + $\frac{1}{2}logl +\frac{1}{2} log32$

which is equal to the second option