Answer:
The Final Temperature of water = 54.48°C.
Explanation:
Given,
Volume of water = 202 mL.
Initial Temperature T₁ = 32°C
Heat energy absorbed = 19 kJ = 19000 Joules
Final Temperature T₂ = ?
Final temperature can be calculated using the formula,
Q = (mass) (ΔT) (Cp)
Here ΔT = T₂ - T₁
Cp = specific heat of water = 4.184 J/g°C.
For finding the mass, we use the formula,
Density = Mass/Volume
Since, Density of water = 1 g/mL.
Mass of water = 202 grams.
Now Substituting all values in the formula Q = (mass) (ΔT) (Cp)
19000 = (202)(T₂ - T₁)(4.184)
Solving, we get,
(T₂ - T₁) = 22.48°C
Therefore, T₂ = 22.48°C + 32°C = 54.48°C.
Therefore, Final Temperature of water = 54.48°C.
