Question

PLEASE HELP!!!!!!!!!!!!!
A compound has the percent composition 47.40% Pd, 28.50% O, 21.40% C, and 2.69% H. Based on this information, which molecular formulas could represent the compound? (Choose more than one answer)


PdO2C2H3

Pd(O2CCH3)2

Pd(O2C2H3)3

PdO4C2H9

Pd2C8H12O8

Answer 1

Answer:

Pd(O2C2H3)2

Explanation:

Percentage composition of elements in the compound:

Pd= 47.40%

O=28.50%

C=21.40%

H= 2.69%

Molar mass of each element

Pd= 106g/mol

O= 16g/mol

C= 12g/mol

H= 1g/mol

Step 1

Find the moles of each element in 100g sample using the formula

no. of moles(n)=mass/molar mass

For Pd: 47.40g/106g/mol

      n=   0.447 moles

For O: 28.50/16

      n= 1.78 moles

For C: 21.40/12

       n= 1.783 moles

For H: 2.69/1

     n= 2.69moles

Step 2

Now divide the no. of moles separately by the smallest number of moles. Smallest number of moles is 0.447

Pd= 0.447/0.447

    = 1

O= 1.78/0.447

  = 3.9=4

C= 1.78/0.447

  = 3.9=4

H= 2.69/0.447

 = 6

Hence empirical formula is PdO4C4H6

The probable molecular formula is $Pd(O_{2}C_{2}H_{3})2$

Answer 2

Answer:

Pd(O2CCH3)2

Explanation:

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