Solution:
Given that,
Jeremy measured the length of an ant as [tex]5 \times 10^{-2}\ meter[/tex]
We have to write the length in standard notation
From given,
[tex]Length = 5 \times 10^{-2}\\\\Length = \frac{5}{10^{2}}\\\\Simplify\\\\Length = \frac{5}{100}\\\\Length = 0.05[/tex]
Thus the length in standard notation is 0.05 meter
Method 2:
[tex]length = 5 \times 10^{-2}\ meter[/tex]
Use the exponent of 10 to determine how many places to move the decimal point
Since exponent is -2, is negative
Thus, we have to move the decimal point to right 2 places
[tex]5 \times 10^{-2} = 0.05[/tex]
Thus the length in standard notation is 0.05 meter