Question

An aircraft is descending with a constant velocity of 480 kmh at an angle of 2.0 to the horizontal. What is the vertical component of the plane's velocity

Answer 1

Answer:

Vy = 4.65 m/s

Explanation:

Since, the airplane is descending at a rate of 480 km/h at an angle of 2° from horizontal. Therefore, its vertical component of velocity shall be given as follows:

Vy = V Sin θ

where,

Vy = Vertical Component of Velocity = ?

V = Velocity of Plane = (480 km/h)(1000 m/1 km)(1 h/3600 s) = 133.33 m/s

θ = Angle = 2°

Therefore,

Vy = (133.33 m/s)(Sin 2°)

Vy = 4.65 m/s