Answer:
Log6(x² y⁶ / z¹⁰)
Step-by-step explanation:
Taking into account that
Log6(x)+log6(y)=log6(xy),
Log6(x)-log6(y)=log6(x/y)
And a×log6(x)=log6(x^a)
We have:
2(log6(x) + 3 log6(y) − 5 log6(z))=
2(log6(x) + log6(y³) − log6(z⁵))
2 log6(x y³ / z⁵)
Log6(x² y⁶ / z¹⁰)