Question

We dissolve 5g of sugar, C12H22O11, in water to make 1L solution. What is the concentration of this solution expressed as molarity.

Answer 1

Answer: M = 0.01 M C12H22O16

Explanation: First convert the mass of C12H22O16 into moles using the molar mass of the compound.

5 g C12H22O16 x 1 mole C12H22O16 / 342 g C12H22O16

= 0.01 mole C12H22O16

To calculate the molarity we will use the following formula.

M = n / L

= 0.01 mole / 1 L

= 0.01 M C12H22O16