Question

Consider a bird that flies at an average speed of 10.7 m/sm/s and releases energy from its body fat reserves at an average rate of 3.70 WW (this rate represents the power consumption of the bird). Assume that the bird consumes 4.00g4.00g of fat to fly over a distance dbdbd_b without stopping for feeding. How far will the bird fly before feeding again

Answer 1

Answer:

455165.278 m

Explanation:

P = Power = 3.7 W

v = Velocity = 10.7 m/s

Amount of fat = 4 g

1 gram of fat provides about 9.40 (food) Calories

Energy given by 4 g of fat

$E=4\times 9.4\times 4186\\\Rightarrow E=157393.6\ J$

Time required to burn the fat

$t=\dfrac{E}{P}\\\Rightarrow t=\dfrac{157393.6}{3.7}\\\Rightarrow t=42538.811\ s$

Distance traveled by the bird

$s=vt\\\Rightarrow s=10.7\times 42538.811\\\Rightarrow s=455165.2777\ m$

The bird will fly 455165.278 m

Answer 2

Answer:

Part A: 455 km

Part B: 8.95 g

Part C: 3.11 g

Explanation:

A: Calculate distance by converting grams of fat to Joules, then using the equations t=W/P and d=v*t.

B: Calculate grams of carbohydrates by the same method.

C: Calculate grams of fat by the same method.