Answer:
The pH value comes out to be 9.03. We will get an alkaline solution by the hydrolysis of the salt of a weak acid and a strong base.
Explanation:
[tex]KC_{2}H_{3}O_{2}[/tex] is a salt of a weak acid acetic acid and a strong base KOH. This salt will hydrolyze in water to give an alkaline solution.
Assuming concentration (C) of the salt to be 0.2 M as it is not given.
[tex]K_{a}[/tex] of acetic acid = [tex]1.8\times 10^{-5}[/tex]
[tex]\textrm{pK}_{a} = -\textrm{ log}\left ( K_{a} \right ) \\\textrm{pK}_{a} = -\textrm{ log}\left ( 1.8\times 10^{-5} \right ) \\\textrm{pK}_{a} = 4.75[/tex]
The formula of pH on hydrolysis of salt of weak acid and strong base is given below
[tex]pH = \displaystyle \frac{1}{2}\left ( pK_{w}+pK_{a}+\textrm{log}C \right ) \\pH = \displaystyle \frac{1}{2} \left ( 14+4.75+\textrm{log}0.2 \right ) \\pH = 9.03[/tex]
The pH of solution comes out to be 9.03
