Answer:
The work done on the object by the force accelerating it is 520.31 J
Explanation:
Given;
mass of an object = 4.3 kg
horizontal velocity of the object, v = 11 m/s
time of acceleration, t = 3.4 s
work done is given as the product of force and distance
Work done = Fd
horizontal distance traveled by the object within 3.4 s, is calculated as follows;
X = Vt + ¹/₂gt², gravity has little or no influence on horizontal displacement, thus g = 0
X = Vt
X = 11*3.4 = 37.4 m
Force on the object, F = ma = m(v/t) = 4.3(11/3.4) = 13.912 N
work done = Fd = 13.912 x 37.4 = 520.31 J
Therefore, the work done on the object by the force accelerating it is 520.31 J
Answer: W=260.174J
Explanation: since the object is stationary, it initial velocity U = 0
final velocity V = 11 m/s, time t = 3.4s, distance S = ?, acceleration a = ? work done W = ? force F = ?
W = FS
a = v-u/t = 11-0/3.4 = 3.2353m/s^2
to calculate the distance, let look at one of the equations of motion
V^2=U^2+2as hence s = V^2-U^2/2a = 11*11/2*3.235 = 18.7017m
But force F = MA (mass*acceleration)
F= 4.3*3.2353 = 13.91179N
therefore work done W = 13.91179*18.7017 = 260.174J
