Step-by-step explanation:
x - y = 7...eqn 1
x^2 + y = 125...eqn 2
making y the subject of the formula in eqn 1
=> y = x -7...eqn 3
subst for y from eqn 3 in eqn 2
=> x^2 + x-7 = 125
=> x^2 + x - 132 = 0
=> (x + 12) (x -11) =0
x = 11 or -12
when x = 11, y = 4
when x = -12, y = -19
Answer:
The largest numbers is either -12 or 11
Step-by-step explanation:
Let the numbers be a and b and a be the largest number.
The difference of two numbers is 7
a - b = 7 ------------------------- eqn 1
The sum of the smaller number and the square of the larger number is 125
a² + b = 125 ------------------------- eqn 2
eqn 1 + eqn 2
a² + a - 132 = 0
( a + 12 ) (a - 11) = 0
a = -12 or a = 11
So the largest numbers is either -12 or 11
