Question

This problem follows up on a discussion from lecture. A wind turbine with an efficiency of 45% for converting wind energy into electrical energy is designed to yield 10 kW of electrical power in a 20 mi/h wind. [The density of air is 1.2 kg/m3.]

What length rotor blades does this wind turbine have?

Answer 1

Answer:

4.1 m

Explanation:

10 kW = 10000 W

20mi/h = 20*1.6 km/mi = 32 km/h = 32 * 1000 (m/km) *(1/3600) hr/s = 8.89 m/s

The power yielded by the wind turbine can be calculated using the following formula

$P = \frac{1}{2} \rho v^3 A C_p$

where $\rho = 1.2 kg/m^3$ is the air density, v = 8.89 m/s is the wind speed, A is the swept area and $C_p = 0.45$ is the efficiency

$10000 = 0.5 * 1.2 * 8.89^3 * A * 0.45$

$10000 = 190A$

$A = 10000 / 190 = 52.7 m^2$

The swept area is a circle with radius r being the blade length

$\pi r^2 = A = 52.7$

$r^2 = 52.7 / \pi = 16.79$

$r = \sqrt{16.79} = 4.1 m$

Answer 2

The length of the rotor blades should be 4.06m.

Calculation of the length:

Since

Electrical power produced = 1/2 ρ Cp A v^3

Here,

Cp is coefficient of performance = 45% = 0.45

Now

A is swept area = pi*r^2

where r is the length of the blade

v is the velocity of wind = 20 mi/hr = 8.9408 m/s

Now

10000 W = 0.5*1.2*0.45*A*8.9408^3

A = 51.8 m^2

r = 4.06 m

Learn more about length here: https://brainly.com/question/14382969