Question

A box of mass 96 kg is at rest on a horizontal frictionless surface. A constant horizontal force F then acts on the box, and accelerates it to the right. It is observed that it takes the box 4.3 seconds to travel 58 meters. What is the magnitude of the force?

Answer 1

Answer:

F = 601.92N

Explanation:

Please see attachment below.

Answer 2

Answer:

601.92 N

Explanation:

Using Newton's equation of kinematics,

F = ma .......................... Equation 1

Where F = force,  m = mass of the box, a = acceleration of the box.

we can look for acceleration using the equation of motion

s = ut+1/2at²................. Equation 2

Where s = distance, u = initial velocity, and t = time.

Given: s = 58 m, t = 4.3 s, u = 0 m/s (at rest)

substitute into equation 2

58 = 0(4.3)+1/2(a)(4.3²)

58 = 9.245a

a = 58/9.245

a = 6.27 m/s²

Also given: m = 96 kg

Substitute into equation 1

F = 96(6.27)

F = 601.92 N