Question

The given line passes through the points (0, -3) and (2,3).
What is the equation, in point-slope form of the line that is
parallel to the given line and passes through the point
(-1, - 1)?
ch
3
.
(
23)
2
N
+
y+1 = -3(x + 1)
+1==3(x + 1)
v+1 ={x + 1)
y+1 = 3(x + 1)
$ 4 3 2 1 1 2 3 4 5 x
-24
0,-3)

Answer 1

Answer:

y + 1 = 3(x + 1)

Step-by-step explanation:

Let D represent the given line

and Δ represent the line that is parallel to the given line and passes through the point (-1, - 1)

slope of D  = $\frac{3-(-3)}{2-0} =3$

Since Δ is parallel to D then Δ has a slope of 3 as well

then the equation of Δ is  y=3x + p (where p is a constant to find out)

Δ passes through (-1 , -1) means -1 = 3(-1) + p then p = 2

finally, Δ: y = 3x + 2

which is the same as  y+1=3((x+1)

Answer 2

Answer:

Trust Them(:

Step-by-step explanation: