Respuesta :
Answer:costC(p)= 1400+20p
R(p)= 4p^2+200p
Profit= 4p^2+ 180p-1400
Step-by-step explanation:
q=4p+200
Student council charge $400 per week.
Revenue= price × quantity.
Relationship between revenue and profit= Revenue-total cost.
Total cost= cost of facilities +(cost of one shirt)× number of T-shirts sold per week.
C(p)= 400 + 5(q)
Put q=4p+200
C(p)= 400 + 5 (4p +200)
C(p)= 400+ 20p + 1000
C(p)= 1400+ 20p
Relationship between revenue and price=Revenue= price × quantity
R(p)= p×q
Put q=4p +200
R(p)= p ×(4p +200)
R(p)= 4p^2+ 200p
Profit= Revenue - total cos
Profit=R(p) -C(p)
Profit= (4p^2 + 200p) - ( 20p +1400)
Profit= 4p^2 + 180p -1400
Answer:
(i) The cost function is C(q) =5q + 400
(ii) The profit function =[tex]5q - q^2 /4[/tex]for weekly profit
(iii) the maximum profit is $243.75
Step-by-step explanation:
(i) the cost function will be C(q) = FC(q) + V(q)
fixed costs FC(q) as a function of quantiyy and variable costs VC(q) we already know that the fixed cost is the $400 per week from charges to use facilities then Variable costs is $5 times the quantity of t shirts sold per week.
so C(q) = $400 + 5q
(ii) The profit function will be found by multiplying quantity demanded with the price at which that quantity is demanded at so we have a demand function q= -4p + 200 then we make the price the subject of the formula
p = 200/4 - q/4 we divided both sides by 4 after transposing -4p
then we get p= 50 - q/4 which is the price of the quantity demanded then we multiply this price by q
thereafter we get pq = 50q - q^2 /4
which is our profit function because p x q is revenue/ profit ;
[tex]Profit = 50q - q^2 / 4[/tex]