Step-by-step explanation:
[tex](26) \\ \frac{m}{3} - 4 \geqslant \frac{m - 2}{4} \\ \\ \therefore \: \frac{m - 12}{3} \geqslant \frac{m - 2}{4} \\ \\ \therefore \:\frac{4(m - 12)}{12} \geqslant \frac{3(m - 2)}{12} \\ \\ \therefore \:4m - 48 \geqslant 3m - 6 \\ \\ \therefore \:4m - 3m \geqslant 48 - 6 \\ \\ \huge \red{ \boxed{\therefore \:m \geqslant 42}} \\ \\ (27) \\ \frac{a}{2} - \frac{a - 3}{3} < 5 - \frac{a}{6} \\ \\ \therefore \: \frac{3a - 2a + 6}{6} < \frac{30 - a}{6} \\ \\ \therefore \: \frac{a + 6}{6} < \frac{30 - a}{6} \\ \\ \therefore \: a + 6 < 30 - a \\ \\ \therefore \: a + a < 30 - 6 \\ \\ \therefore \: 2 a < 24 \\ \\ \therefore \: a < \frac{24}{2} \\ \\ \huge \orange{ \boxed{\therefore \: a < 12}}[/tex]
