Answer:
[tex]\huge\color{yellow}\boxed{\colorbox{black}{Answer ☘}}[/tex]
[tex]r = 9 \cotθ \cscθ[/tex]
ѕtєp вч ѕtєp єхplαnαtíσn...
[tex]x = r \cosθ \\ y = r \sinθ \\ \\ substitute \: for \: x \: and \: y, \\ \\ \\ ({r \sinθ})^{2} = 9(r \cosθ) \\ r {}^{2} \sin {}^{2} θ = 9r \cosθ \\ r {}^{2} \sin {}^{2}θ - 9r \cosθ = 0 \\ r(r \sin {}^{2} θ - 9 \cosθ )= 0[/tex]
at this point...
[tex]r \sin {}^{2} θ = 9 \cosθ \\ r = \frac{9 \cos θ}{ \sin {}^{2} θ } \\ r = \frac{9 \cosθ }{ \sinθ } \times \frac{1}{ \sinθ } \\ \\ remember..... \\ \frac{cosθ}{sinθ}=cotθ \: \: and \: \:\frac{1}{ \sinθ } = \cscθ \\ \\ r = 9 \cotθ \cscθ[/tex]
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