Question

A current of 1.90 A flows through a wire. How many electrons pass through that wire in 1 second? The charge of an electron is 1.602 x 10^-19 C

Answer 1

Answer:

n=1.18 x 10¹⁹

Explanation:

Given that

Current in the wire ,I = 1.9 A

The charge =q = n e

We know that

$I=\dfrac{q}{t}$

I=Current

q=Charge

t=time

$t=\dfrac{q}{I}$

Now by putting the values in the above equation we get'

q= 1.9 x 1 C

q= 1.9 C

q= n e

$n=\dfrac{1.9}{1.602\times 10^{-19}}$

n=1.18 x 10¹⁹