Respuesta :
Answer:
Step-by-step explanation:
The percentage of high school students who drink and drive at the beginning of 2001 = 17.5%
The percentage of high school students who drink and drive at the beginning of 20011 = 10.3%
Rate of decrease = 17.5 - 10.3 / 10
= .72
The required linear function
f(t) = - 0.72 x t + 17.5
b ) Rate of decrease in percentage = (17.5 - 10.3) / 10
= .72 %
c ) Percentage of high school students who drink and drive at the beginning of 2014
t = 2014 - 2011 = 13
f(t) = - 0.72 x t + 17.5
= - .72 x 13 + 17.5
= 8.14 %
In this exercise we have to use knowledge about probability and percentage to calculate the linear function so:
A)[tex]f(t) = - 0.72 T + 17.5[/tex]
B)[tex]R= 0.72 \%[/tex]
C)[tex]f(t)=8.14 \%[/tex]
So we have to use the knowledge informed in the statement, we have as:
- The percentage of high school students who drink and drive at the beginning of 2001 = 17.5%
- The percentage of high school students who drink and drive at the beginning of 20011 = 10.3%
To calculate the rate of increase we find that:
[tex]R = 17.5 - 10.3 / 10\\R=0 .72\\f(t) = - 0.72 T + 17.5[/tex]
b ) Making the rate decrease as a percentage is:
[tex]R = (17.5 - 10.3) / 10\\R= 0.72 \%[/tex]
c ) Percentage of high school students who drink and drive at the beginning of 2014, will be:
[tex]t = 2014 - 2011 = 13\\f(t) = - 0.72 x t + 17.5\\f(t)= - .72 x 13 + 17.5= 8.14 \%[/tex]
See more about probability at brainly.com/question/743546