Isotonic saline solution, which has the same osomotic pressure as blood, can be prepared by dissolving 0.923 g of NaCl in enough water to produce 100. mL of solution. What is the osmotic pressure of this solution at 25 ∘C?

Respuesta :

Answer:

3.86 atm

Explanation:

π = M . R .T →  Formula for the osmotic pressure

Let's determine M (mol/L)

(mass / molar mass) / L → (0.923 g / 58.45 g/mol) / 0.1L = 0.158 M

T = 25°C + 273 → 298K

We can now replace the data given:

π = 0.158 M . 0.082 . 298 K → 3.86 atm

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