Answer : The pressure of the helium gas inside the container would be, 32.1 atm
Explanation :
To calculate the pressure of the gas we are using ideal gas equation as:
[tex]PV=nRT[/tex]
where,
P = Pressure of [tex]He[/tex] gas = ?
V = Volume of [tex]He[/tex] gas = 7.5 L
n = number of moles [tex]He[/tex] = 10 mole
R = Gas constant = [tex]0.0821L.atm/mol.K[/tex]
T = Temperature of [tex]He[/tex] gas = [tex]20^oC=273+20=293K[/tex]
Putting values in above equation, we get:
[tex]P\times 7.5L=10mole\times (0.0821L.atm/mol.K)\times 293K[/tex]
[tex]P=32.1atm[/tex]
Thus, the pressure of the helium gas inside the container would be, 32.1 atm