Answer:
D.V.= - 1.34 %
Explanation:
Given that
V₁=50,000 L
T₁=25⁰C = 273 + 25 K =298 K
The final temperature ,T₂= 25 - 4 ⁰C = 21 ⁰C
T₂ = 21 + 273 K= 294 K
We know that for constant pressure process
[tex]V_2=\dfrac{T_2}{T_1}\times V_1[/tex]
[tex]V_2=\dfrac{294}{298}\times 50000\ L[/tex]
V₂=49328.85 L
The percent decrease in the volume is given as
[tex]D.V.=\dfrac{49328.85-50000}{50000}\times 100[/tex]
D.V.= - 1.34 %