Respuesta :
Answer: x:y = 2:5
Step-by-step explanation:
Given : The prices of two radios are in the ratio x:y
When the prices are both increased by £20, the ratio becomes 5:2
Then,
When the prices are both reduced by £5, the ratio becomes 5:1
Then,
Subtract (2) from (1), we get
Put this value in (2), we get
Now, the ratio of x:y=
Dividing 4 from both the numerator and denominator, we get
x:y= =2:5
Credit: JeanaShupp
Step-by-step explanation:
Given : The prices of two radios are in the ratio x:y
When the prices are both increased by £20, the ratio becomes 5:2
Then,
When the prices are both reduced by £5, the ratio becomes 5:1
Then,
Subtract (2) from (1), we get
Put this value in (2), we get
Now, the ratio of x:y=
Dividing 4 from both the numerator and denominator, we get
x:y= =2:5
Credit: JeanaShupp
Answer:
4:1
Step-by-step explanation:
x+20 : y+20 = 5 : 2
(x+20)/(y+20) = 5/2
2(x+20) = 5(y+20)
2x+40 = 5y+100
2x = 5y+60 (1)
x-5 : y-5 = 5:1
(x-5)/(y-5) = 5/1
x-5 = 5(y-5)
x-5 = 5y-25
x = 5y-20 (2)
Solve (1) & (2) simultaneously,
2(5y-20) = 5y+60
10y-40 = 5y+60
5y = 100
y = 20
x = 5y-20
x = 5(20)-20 = 100-20
x = 80
x:y
80:20
4:1