Question

A 2.4 μC point charge is placed in an external uniform electric field that has a magnitude of 39000 N/C. At what distance from the charge is the net electric field zero?

Answer 1

Answer:

0.744 m

Explanation:

The electric field (E) = kq/r²

E = 39000 N/C

q = 2.4 μC = 2.4 × 10^-6 C

k = 9 × 10^9

make r the subject

r = √(kq/E)

substitute the data's into the equation

r = 0.744 m

note that

Enet = E1 - E2 = 0

Enet = kq1/r² - kq2/r²

at a distance of 0.744 m is when net electric field = 0