Use the table to write a linear function that relates y to x

Answer:
Therefore the linear equation required is [tex]y = \frac{2}{3} x + 5[/tex]
Step-by-step explanation:
i) from the table we can take the linear function that relates y to x be such that y = mx + c
ii) we see that when x = 0 then y = 5. From this we can conclude that c = 5.
iii) therefore y = mx + 5.
iv) when x = -3 then y = 3, Therefore 3 = -3m + 5, Therefore [tex]m = \frac{2}{3}[/tex]
v) therefore when x = 3 we get [tex]y = \frac{2}{3} x + 5 \Rightarrow y = \frac{2}{3} \times 3 + 5 \Rightarrow y = 2 + 5 = 7[/tex]
therefore the equation satisfies the third pair given
vi) therefore when x = 6 we get [tex]y = \frac{2}{3} x + 5 \Rightarrow y = ( \frac{2}{3} \times 6 )+ 5 \Rightarrow y = 4 + 5 = 9[/tex]
therefore the equation satisfies the fourth pair given.
Therefore the linear equation required is [tex]y = \frac{2}{3} x + 5[/tex]