Respuesta :

Answer:

Therefore the linear equation required is [tex]y = \frac{2}{3} x + 5[/tex]

Step-by-step explanation:

i) from the table we can take the linear function that relates y to x be such that y = mx + c

ii) we see that when x = 0 then y = 5. From this we can conclude that c = 5.

iii) therefore y = mx + 5.

iv) when x = -3 then y = 3, Therefore 3 =  -3m + 5, Therefore  [tex]m = \frac{2}{3}[/tex]

v) therefore when x = 3 we get   [tex]y = \frac{2}{3} x + 5 \Rightarrow y = \frac{2}{3} \times 3 + 5 \Rightarrow y = 2 + 5 = 7[/tex]

therefore the equation satisfies the third pair given

vi)  therefore when x = 6 we get   [tex]y = \frac{2}{3} x + 5 \Rightarrow y = ( \frac{2}{3} \times 6 )+ 5 \Rightarrow y = 4 + 5 = 9[/tex]

therefore the equation satisfies the fourth pair given.

Therefore the linear equation required is [tex]y = \frac{2}{3} x + 5[/tex]

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