The length of the square that has the same perimeter as the rectangle is of length 6cm and area of 48cm² is 7cm
Let's call:
[tex]A_{s}:Area \ of \ square \\ \\ A_{r}:Area \ of \ rectangle \\ \\ P_{s}:Perimeter \ of \ square \\ \\ P_{r}:Perimeter \ of \ rectangle[/tex]
From the question, we know that:
So:
[tex]P_{s}=P_{r}[/tex]
Moreover:
Accordingly:
[tex]For \ Rectangle: \\ \\ L:Length \\ W:Width \\ \\ A_{r}=L\times W \\ \\ 48=6W \\ \\ W=8[/tex]
Also:
[tex]A_{s}=s^2 \\ \\ S:Side \ of \ square[/tex]
From the statement of perimeters:
[tex]P_{s}=P_{r} \\ \\ \\ But: \\ \\ P_{s}=4s \\ \\ P_{r}=2W+2L \\ \\ \\ Then: \\ \\ 4s=2W+2L \\ \\ \\ But: \ W=8 \ and \ L=6 \\ \\ 4s=2(8)+2(6) \\ \\ 4s=16+12 \\ \\ 4s=28 \\ \\ \boxed{s=7cm}[/tex]
Finally, the length of the square that has the same perimeter as the rectangle is of length 6cm and area of 48cm² is 7cm
Perimeter: https://brainly.com/question/9969486
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