What are the potential solutions

Answer: [tex]x = -2 \ and \ x = -4[/tex]
Step-by-step explanation:
Alright, lets get started.
The given equation is :
[tex]2ln(x+3)=0[/tex]
Using the property of logs : [tex]If \ log_{a}m=n, \ then \ a^n=m[/tex]
So using this property in our equation
[tex]e^0=(x+3)[/tex]
[tex](x+3)=e^0[/tex]
[tex]x+3=1[/tex]
Subtracting 3 in both sides
[tex]x+3-3=1-3[/tex]
[tex]x=-2[/tex]
There is only one option with x as -2, hence part b is the answer. .......Answer
Hope it will help :)