Question

In a double-slit experiment the distance between slits is 5.5 mm and the slits are 1.0 m from the screen. Two interference patterns can be seen on the screen: one due to light with wavelength 480 nm, and the other due to light with wavelength 565 nm. What is the separation on the screen between the third-order (m)?

Answer 1

Answer:

The separation on the screen between the third-order (m) is 46.36 μm

Explanation:

Given

Distance between slits is = 5.5 mm

a = 5.5 mm

Distance between slits and screen is 1.0 m

D = 1.0 m

Wavelength

y1 = 480 nm and y2 = 565 nm

imy1 = m * $\frac{y1D}{a}$

imy2 = m * $\frac{y2D}{a}$

when m = 3 (third-order)

Δi = i3y2 - i3y1 = 3 * $\frac{(y2 - y1) D}{a}$

Δi = 46.36 μm