The equation of the line is [tex]5x+y-38=0[/tex]
Step-by-step explanation:
The slope is [tex]m=-5[/tex]
Also, the line passes through the points [tex](7,3)[/tex]
To find a line with slope [tex]m=-5[/tex] that passes through the points [tex](7,3)[/tex], let us use the equation of a line with slope that passes through the point is given by [tex](y-y_{1} )=m(x-x_{1} )[/tex] where m is the slope and [tex](x_{1} ,y_{1} )[/tex] are the points [tex](7,3)[/tex].
Thus, substituting the values in the equation of a line, we get,
[tex](y-3)=-5(x-7)[/tex]
Multiplying the term [tex](x-7)[/tex] by -5, we get,
[tex]y-3=-5 x+35[/tex]
Adding both sides by 5x,
[tex]5x+y-3=35[/tex]
Subtracting 35 from both sides of the equation,
[tex]5x+y-38=0[/tex]
Thus, the equation of the line is [tex]5x+y-38=0[/tex]