brandencheeks19 brandencheeks19

30-10-2017
Mathematics

contestada

Solve this quadratic equation using the quadratic formula. (3 - y)(y + 4) = 3y - 5

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daijingyi722 daijingyi722

30-10-2017

-y^2-4y+3y+12=3y-5
-y^2-4y+17=0
b^2-4ac=(-4)^2-4*(-1)*17=16+68=84
y=(4 plus or minus 2√21)/(-2)= -2 plus or minus √21

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areli12318 areli12318

13-01-2021

Answer:

y=(4 plus or minus 2√21

Step-by-step explanation:

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