Answer:
[tex]m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3 )[/tex]
Explanation:
Then the mass of the material required to make such a sphere would be calculated as:
Total volume of the spherical shell:
[tex]V_t=\frac{4}{3} \pi.r_2^3[/tex]
And the volume of the hollow space in the sphere:
[tex]V_h=\frac{4}{3} \pi.r_1^3[/tex]
Therefore the net volume of material required to make the sphere:
[tex]V=V_t-V_h[/tex]
[tex]V=\frac{4}{3} \pi(r_2^3-r_1^3)[/tex]
Then the mass of the material used is:
[tex]m=\rho.V[/tex]
[tex]m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3 )[/tex]