Answer:
The formation of ether from alkene and alcohol in the presence of an acid take place in four steps.
Step 1:
In first step the oxygen atom of alcohol abstracts the proton of acid and becomes a strong conjugate acid.
Step 2:
Double bond of alkene being electron rich and nucleophilic in nature adds the proton from alcohol across its double bond and forms a stable carbocation (i.e. in this case a 2° carbocation).
Step 3:
The oxygen atom of alcohol now attacks the electrophilic carbon (i.e. carbocation).
Step 4:
The conjugate base of acid catalyst formed in first step abstracts the proton from oxonium ion and allows the final product to form as shown in attached reaction mechanism.
