Answer:
6 atm.
Explanation:
Let the mass of both be m
Then moles of He = m/ 4
Moles of Ne = m/ 20
mole fraction of He = Moles of He/ Total moles = m/4/ (m/4 + m/20) = 0.25 m/0.3m = 0.83
Pressure of He = Mole fraction×total pressure = 0.83 × 6 atm = 5 atm
Answer:
The partial pressure of He is [tex]5\rm atm[/tex]
Explanation:
Given information:
Total pressure [tex]p_{total}=6\rm atm[/tex]
Assume that mass of both He and Ne is =[tex]m[/tex]
So we know that
[tex]n=\frac{m}{M}[/tex]
where,m mass of substance and M is molar mass of substance
Moles of He=[tex]\frac{m}{4}[/tex]
Moles of Ne=[tex]\frac{m}{20}[/tex]
Mole fraction of He
[tex]\chi_{He}[/tex]=Moles of He/Total moles
[tex]\chi_{He}=\frac{m/4}{m/4+m/20}=0.83[/tex]
By use of Dalton's equation,
[tex]\chi_{He}=\frac{p_{He}}{p_{total}}[/tex]
On substitution,
[tex]{p_{He}}}=\chi_{He}\times{p_{total}=0.83\times 6\rm atm=5atm[/tex]
Hence, the partial pressure of He is [tex]5\rm atm[/tex] .
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