Given:
The ratio of the number of Rs2 coins to the number of Rs5 coins is 1:3.
The value of all the Rs5 coins is Rs45.
To find:
The value of all the Rs2 coins in the box.
Solution:
Let x be the number of Rs2 coins and y be the number of Rs5 coins.
The value of all the Rs5 coins is Rs45.
[tex]5y=45[/tex]
[tex]y=\dfrac{45}{5}[/tex]
[tex]y=9[/tex]
The ratio of the number of Rs2 coins to the number of Rs5 coins is 1:3.
[tex]\dfrac{x}{y}=\dfrac{1}{3}[/tex]
[tex]\dfrac{x}{9}=\dfrac{1}{3}[/tex]
Multiply both sides by 9.
[tex]\dfrac{x}{9}\times 9=\dfrac{1}{3}\times 9[/tex]
[tex]x=3[/tex]
The value of all the Rs2 coins in the box is:
[tex]\text{Required value}=2x[/tex]
[tex]\text{Required value}=2(3)[/tex]
[tex]\text{Required value}=6[/tex]
Therefore, the value of all the Rs. 2 coins in the box is Rs. 6.