Question

A preliminary study of the fall lobster catch showed that for 35 lobsters selected at random the mean weight was 2.9 pounds with standard deviation of .6 pounds find a 90% confidence interval for the population mean of the fall lobster.

Answer 1

Answer: = ( 2.73, 3.07)

Therefore at 90% confidence interval (a,b) = ( 2.73, 3.07)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean gain x = 2.9

Standard deviation r = 0.6

Number of samples n = 35

Confidence interval = 90%

z(at 95% confidence) = 1.645

Substituting the values we have;

2.9+/-1.645(0.6/√35)

2.9+/-1.645(0.1014)

2.9+/-0.167

2.8+/-0.17

= ( 2.73, 3.07)

Therefore at 90% confidence interval (a,b) = ( 2.73, 3.07)