Let...
a=number of adult tickets
c=number of children tickets
Equations:
a+c=8
15a+10c=105
Solve by substitution.
a+c=8 -----> a=8-c
15a+10c=105
15(8-c)+10c=105
120-15c+10c=105
120-5c=105
-5c=-15
c=3
a+3=8
a=5
answer: 3 children tickets and 5 adult tickets