Answer:
Pressure will decrease according to the Charles Gay Lussac law.
Explanation:
When there is a gas in a tank, and the moles of gas are not modified, neither the volume, we can notice that pressure will be modifying, in order to the absolute temperature, as directly proportion.
T° increase → Pressure increase
T° decrease → Pressure decrease
If the pressure keeps on constant, it will be the volume that would be modified according to the absolute T°, as a directly proportion.
Volume increase → T° increase
Volume decrease → T° decrease
Let's go to the maths
P₁ / T₁ = P₂/T₂
100 kPa / 333K = P₂ / 283K
(100 kPa / 333K) . 283K = P₂ → 84.9 atm
As T° has decreased, pressure also decreased.
