Respuesta :

[tex] \huge \colorbox{pink}{Question } [/tex]

solve this system using substitution x+5y=-32 y=3x

Substitute 3x for y in x + 5y = - 32

[tex]x + 5y = - 32 \\ x + 5(3x) = - 32 \\ x + 15x = - 32 \\ 16x = - 32 \\ \frac{16x}{16} = \frac{ - 32}{16} \\ x = - 2[/tex]

Substitute - 2 for for x in y = 3x

[tex]y = 3x \\ y = 3( - 2) \\ y = - 6[/tex]

[tex] \huge \colorbox{pink}{Answer} [/tex]

x = - 2

y = - 6

Hope it helps ^_^

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