Which equation represents the line that is perpendicular to y= 3/4x + 1 and passes through (-5, 11)
A. Y = - 4/3x + 13/3
B. Y = - 4/3x + 29/3
C. Y = 3/4x + 59/4
D. Y = 3/4x - 59/4

Respuesta :

The equation which represents the perpendicular line is y = [tex]-\frac{4}{3}[/tex]  x  +  [tex]\frac{13}{3}[/tex]  ⇒ A

Step-by-step explanation:

Let us revise the relation between the slopes of the perpendicular lines

  • The product of the slopes of the perpendicular lines is -1
  • That means if the slope of one of them is m, then the slope of the other is
  • reciprocal the slope of a line and change its sign to find the slope of the perpendicular line to it

The form of the linear equation is y = m x + b, where m is the slope of the line and b is the y-intercept (y at x = 0)

∵ The equation of the given line is y = [tex]\frac{3}{4}[/tex] x + 1

- Compare it with form of the equation above

∴ m =  [tex]\frac{3}{4}[/tex]  ⇒ slope of the given line

- To find the slope of the perpendicular line reciprocal it and

  change its sign

∴ The slope of the perpendicular line = [tex]-\frac{4}{3}[/tex]

Let us write the equation of the perpendicular line

∵ y = m x + b

∴ y =  [tex]-\frac{4}{3}[/tex] x + b

- To find b substitute x and y in the equation by the coordinates

  of a point on the line

∵ The perpendicular line passes through the point (-5 , 11)

∴ x = -5 and y = 11

- Substitute it in the equation

∴ 11 =   [tex]-\frac{4}{3}[/tex] (-5) + b

∴ 11 = [tex]\frac{20}{3}[/tex] + b

- Subtract  [tex]\frac{20}{3}[/tex]  from both sides

∴ [tex]\frac{13}{3}[/tex] = b

∴ y =  [tex]-\frac{4}{3}[/tex]  x  +  [tex]\frac{13}{3}[/tex]

The equation which represents the perpendicular line is

y = [tex]-\frac{4}{3}[/tex]  x  +  [tex]\frac{13}{3}[/tex]

Learn more:

You can learn ore about the perpendicular lines in brainly.com/question/2601054

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Answer:

The answer is A. y= -4/3x + 13/3

Step-by-step explanation.

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