Question

When opening a door, you push on it perpendicularly with a force of 55.0 N at a distance of 0.850m from the hinges. What torque are you exerting relative to the hinges?

Answer 1

Answer:

Torque exerted = 46.75Nm

Explanation:

A Torque (τ) is a force that tends to cause rotation.

Mathematically, it is given by;

τ = F * r sin Θ

where F is the linear force, r is the distance from the axis of rotation to the point where the force is applied and Θ is the angle between the Force (F) and the distance (r).

In the question,

F = 55.0N

r = 0.850m

Θ = $90^{0}$ since the force is perpendicular on the door

Therefore;

τ = F * r sin Θ

Substituting the values of F, r and Θ into the equation gives

τ = 55.0 * 0.850 sin $90^{0}$

τ = 46.75Nm

Hope this helps!