Question

can someone pls help w finding the x and y intercepts of this?

y=x^2-2x

Answer 1

Answer:

y-intercept is 0, x-intercept is 0 and 1

Step-by-step explanation:

For y-intercept, x=0 :

${ \tt{y = {(0)}^{2} - 2(0) }} \\ { \tt{y = 0}}$

For x-intercept, y=0 :

${ \tt{0 = {2x}^{2} - 2x }} \\ { \tt{2x(x - 1) = 0}} \\ { \tt{x = 0 \: \: and \: \: 1}}$