Biologists have noticed that the chirping of crickets of a certain species is related to temperature, and the relationship appears to be very nearly linear. A cricket produces 112 chirps per minute at 74 degrees Fahrenheit and 179 chirps per minute at 82 degrees Fahrenheit..

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Answer:

[tex]T(N)=\frac{67}{8}N-\frac{2031}{4}[/tex]

Step-by-step explanation:

Please consider the complete question.  

Biologists have noticed that the chirping rate of crickets of a certain species is related to temperature, and the relationship appears to be very nearly linear. A cricket produces 112 chirps per minute 74° F at and 179 chirps per minute at 82°F. Find a linear equation that models the temperature T as a function of the number of chirps per minute N.

We have been given two points on the line [tex](74,112)[/tex] and [tex](82,179)[/tex].

First of all, we will find the slope of the line using given points as:

[tex]\text{Slope}=m=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\frac{179-112}{82-74}[/tex]

[tex]m=\frac{67}{8}[/tex]

Now, we will points-slope form of an equation to write our required equation as:

[tex](y-y_1)=m-(x-x_1)[/tex]

[tex](y-112)=\frac{67}{8}-(x-74)[/tex]

[tex](y-112)=\frac{67}{8}(x-74)[/tex]

[tex]y-112=\frac{67}{8}x-\frac{67}{8}*74[/tex]

[tex]y-112+112=\frac{67}{8}x-\frac{67}{8}*74+112[/tex]

[tex]y=\frac{67}{8}x-\frac{67}{4}*37+\frac{4*112}{4}[/tex]

[tex]y=\frac{67}{8}x-\frac{2479}{4}+\frac{448}{4}[/tex]

[tex]y=\frac{67}{8}x-\frac{2031}{4}[/tex]

Since we are required to write temperature T as a function of the number of chirps per minute N, so we will get:

[tex]T(N)=\frac{67}{8}N-\frac{2031}{4}[/tex]

Therefore, our required function would be  [tex]T(N)=\frac{67}{8}N-\frac{2031}{4}[/tex].

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