Question

The radius of the cone is 1.25 inches, and its height is 2.75 inches. If the diameter of the bubble gum ball is 0.5 inches, what is the closest approximation of the volume of the cone that can be filled with flavored ice? .A) 4.43 in3 . B) 0.07 in3 . C) 13.50 in3 . D) 4.50 in3 . .

Answer 1

Answer:

Option D) 4.50 in3

Step-by-step explanation:

step 1

Find out the volume of the cone

The volume of the cone is

$V=\frac{1}{3}\pi r^{2} h$

we have

$r=1.25\ in$

$h=2.75\ in$

assume

$\pi =3.14$

substitute

$V=\frac{1}{3}(3.14)(1.25^{2})(2.75)$

$V=4.50\ in^3$

step 2

Find out the volume of the sphere (bubble gum)

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

we have

$r=0.5/2=0.25\ in$ -----> the radius is half the diameter

assume

$\pi =3.14$

substitute

$V=\frac{4}{3}(3.14)(0.25^{3})$

$V=0.07\ in^3$

step 3

Find out the volume of the cone that can be filled with flavored ice

Sum the volumes

$V=4.50+0.07=4.57\ in^3$

therefore

The closest approximation of the volume of the cone that can be filled with flavored ice is 4.50 in3